4x+x^2-5/3=0

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Solution for 4x+x^2-5/3=0 equation: 


x in (-oo:+oo)

x^2+4*x-(5/3) = 0

x^2+4*x-5/3 = 0

x^2+4*x-5/3 = 0

DELTA = 4^2-(-5/3*1*4)

DELTA = 68/3

DELTA > 0

x = ((68/3)^(1/2)-4)/(1*2) or x = (-(68/3)^(1/2)-4)/(1*2)

x = ((68/3)^(1/2)-4)/2 or x = (-((68/3)^(1/2)+4))/2

x in { (-((68/3)^(1/2)+4))/2, ((68/3)^(1/2)-4)/2 }

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